Question

The hypotenuse of an isosceles triangles measures 10 inches long. What is the length of one leg of the triangle?

Answer 1

In order to be an isosceles triangle with a hypotenuse, it must be a 45/45/90 triangle!
\[x ^{2}+x ^{2}=10^{2}\]
\[2x ^{2}=100\]
\[x ^{2}=50\]
\[x=\sqrt{50}\]
\[x=\sqrt{25}\times \sqrt{2}\]
\[x=5*\sqrt{2}\]
\[x=5\sqrt{2}\]

Answer 2

@jodecci

Answer 3

would 10 over 2 squar rooted be the same? @Aveline

Answer 4

This?\[\frac{ 10 }{ \sqrt{2} }\] or this?\[\sqrt{\frac{ 10 }{ 2 }}\]

Answer 5

top one @Aveline

Answer 6

@jodecci
It would be the same thing. However, your teacher may not want radicals in your denominator.

Answer 7

okay thank you so much