Given 🔺ABC with a = 24 b=13.75, angle A = 108⁰ and angle B = 33⁰, find c. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.
39.00
17.83
15.87
13.74
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RhondaSommer (rhondasommer):
Sean :)
OpenStudy (sweetburger):
Angle C is found easily by 180 - 108 -33 = 39
RhondaSommer (rhondasommer):
|dw:1461253655403:dw|
hmm ok
OpenStudy (sweetburger):
So we use the law of sins again
because it states
\[\sin(c)/c = \sin(a)/a = \sin (b) /b\]
so we will only consider
\[\sin(a)/a = \sin(c)/c\]
OpenStudy (sweetburger):
\[\sin(108)/(24) = \sin(39)/c \]
solve for c
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RhondaSommer (rhondasommer):
0.951*C=24*0.629
0.951*C=15.096
C=15.87
OpenStudy (sweetburger):
looks good @RhondaSommer
RhondaSommer (rhondasommer):
sweer
RhondaSommer (rhondasommer):
Given 🔺ABC with a = 9 angle A = 80⁰ and angle B = 35⁰, find b. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.
5.24
6.53
8.28
67.00