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Find the derivatuve f(x)=-7/x at x=-3
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\[\frac{\partial }{\partial x}\left(-\frac{7}{x}\right)=\frac{7}{x^2} \]At x = -3, 7/x^2 = 7/9
Oh okay I get it now thanks!
Your welcome. The notation is for taking the partial derivative. x is the only variable so the partial derivative is the normal derivative.
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