Question

Which of the following systems is equivalent to the given system?

2/3x - y = 2
x + 1/2y = -3

2x - 3y = 6 and 2x + y = 6
6x - 3y = 6 and 2x + y = 10
2x - 3y = 6 and 2x + y = -6

Answer 1

2/3x - y = 2
multiply by 3
2x-3y=6
x + 1/2y = -3
multiply by 2
2x+y=-6
2x-3y=6
2x+y=-6
The third system is the same
2x - 3y = 6 and 2x + y = 6
6x - 3y = 6 and 2x + y = 10
2x - 3y = 6 and 2x + y = -6

Answer 2

Hints: You are given 2 equations.

Multiply all terms of the first equation by 3 to eliminate the fraction (1/3).

Multiply all terms of the second equation by 2 to eliminate the fraction (1/2).

Note: It's important that you enclose those fractions in parentheses, as I have.

Answer 3

There

Answer 4

hope i helped