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If Alice does 10 Joules of work while pushing Jeff in 5 seconds, and the force of friction due to the broken toboggan did 2 joules of work, how much work did Alice exert?
it should be how much power did alice exert?
here are the choices 50 W 2 W 1.6 W 1.5 W
\[W - W_{friction} = net~work \] \[10-2 = 8 J \] then I knew power was Joules/time \[\frac{ 8J }{ 5s } = 1.6 W \]
BTW my answer is wrong
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Power is the rate of doing work. (P= W/t) \(Work = F_{applied}• displacement. \) Work applied by Alice is different from the work applied by the friction. In this problem you are only concerned about Alice's work.
okay so power only applies to the work done by a particular source right?
yeah
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