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How to simplify (x-1)[-x-2lnabs(x-1)+(x+1)lnabs(x-1)]?
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\[(x-1)[-x-2\ln \left| x-1 \right|+(x+1)\ln \left| x-1 \right|]\]
begin by taking \(\ln \left| x-1 \right|\) as a common factor: \[(x-1)\left[ -x-2\ln \left| x-1 \right|+(x-1)\ln \left| x-1 \right| \right]\] \[(x-1)\left[ -x+\ln \left| x-1 \right|(x+1-2) \right]\] \[(x-1)\left[ -x+\ln \left| x-1 \right|(x-1) \right]\]
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