Question

i'm trying to understand my final practice on paper for my final

How do i go about doing this problem? Its in the comments thank you

Answer 1

\[\log _{3}(x)+\log_{3}(x-4)=2\]

Answer 2

sorry that's supposed to be subtraction not addition

Answer 3

log(a) + log(b) = log(a*b)

Answer 4

then it would be division

Answer 5

log(a) - log(b) = log(a/b)

Answer 6

\[\log _{3}(x \div x-4)=2\]

Answer 7

\[\Large \log_a b = c\]then \[\Large b = a^c\]

Answer 8

now i just simply solve?

Answer 9

my answer sheet is telling me i need to divide by 8, i don't know where the 8 came from

Answer 10

@agent0smith

Answer 11

Did you see my last post...?

Answer 12

@agent0smith