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find value of 2^2^2^2..., power to 2 infinetly many times
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I define this as x, and I say \[2^{x}=x\]
but I could find a solution, wolfram alpha gives me a complex number which is weid since this is a real number
My friend give this to me and said he couldnt do it
First, you've got to check if it converges.
shoot, I forgot
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becuase the first part is 2*sqrt(2*sqrt(...) and I got 4
so naturally I used the same method and thins are screwed this time
Yeah, it simply doesn't converge.
thx, but how do I check for convergencce, I am out of math for about a year
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