Probability :
A poorly-run restaurant messes up one order in three. You and two people from work each eat there
once this month, each of you eating there on a different day. What is the probability that this month the
restaurant didn’t mess up any of the orders placed by your or your two friends? (Your answer should be a
fraction. Assume independence.)

Question

Probability :
A poorly-run restaurant messes up one order in three. You and two people from work each eat there
once this month, each of you eating there on a different day. What is the probability that this month the
restaurant didn’t mess up any of the orders placed by your or your two friends? (Your answer should be a
fraction. Assume independence.)

bmk614 · Answer

The probably that The restaurant won't mess up is 2/3.
That is for one person.
You multiply the probability for you and each of your two other friends.
So you would do (2/3)(2/3)(2/3)

bmk614 · Answer

This would give you (8/27)