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round 1 start solve the following equation when 3x-4>4<6x-2
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hint: subtract 3x from both sides
there is 3 sides
right, so subtract 3x from everything
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6x-2 - 3x = ?
so 3x-2
good! 3x-4 - 3x = ?
-4
good
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now we have: -4 > 4 - 3x < 3x - 2 we can split the inequality into two pieces
-4 > 4 - 3x solve for x
0>-3x
keep going
0<x
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good now solve 4 - 3x < 3x - 2
6-3x<3x 6<6x 1<x
hm, I might have been wrong, let's try a diff method try and solve: 3x-4>4 and 4<6x-2
sorry for the confusion
x>3/8 and x <1
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good ^ that should be your answer (weird question)
thanks bro
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