Calculus 3 Questions....

Question

thecalchater · Answer

@welshfella

thecalchater · Answer

@welshfella  @Loser66 @mathstudent55 @mathmath333 @IrishBoy123 @agent0smith @Luigi0210 
Can you guys help i am pretty much clueless....

bobo-i-bo · Answer

Haha, calchater, fitting name.

bobo-i-bo · Answer

Draw graphs and diagrams to help! :)

thecalchater · Answer

the first one looks like this |dw:1461702610543:dw|

bobo-i-bo · Answer

I'm afraid you have to draw better than that. :P The correct points of intersections are kinda crucial...

irishboy123 · Answer

when it was sober it looked like this https://i.gyazo.com/cc404263ee76835aa40e13e6c291c843.png

agent0smith · Answer

Yeah... use something better than hand drawn diagrams http://www.wolframalpha.com/input/?i=region+bounded+by+x%3D36-y%5E2,+x%3Dy-6

bobo-i-bo · Answer

And then you need to figure out which bit is the enclosed area and figure out integrating what with respect to what gives what areas

thecalchater · Answer

yeah i was going to screen shot it.... Hahahahah Irish XD

agent0smith · Answer

The first one is easy to integrate wrt y. It's a pain to integrate wrt x.

thecalchater · Answer

well it is enclosed at the points where irish has it so where do i go from there?

thecalchater · Answer

How do I go from there as far as solving for the area?

thecalchater · Answer

I got number 3. Just need help on 1 and 2

irishboy123 · Answer

|dw:1461703300455:dw|

not very clever but it should work

Integral = 

top half in ie Q1 + that little triangle in Q2

+ 

bottom half [ie Q3 + Q4] - bigger triangle in Q3