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Another check of an integral? o_o
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ok. and fyi, please put it in the question already. like right below "Another check of an integral?"
\[\int\limits \frac{ x-5 }{ -2x+2 } = \int\limits \frac{ x-1 }{ -2(x-1) } - \int\limits \frac{ 4 }{ -2(x-1) }\]
well. this one is kind of hard for me, 7th grade advanced honors can only help so far.
\[-\frac{ 1 }{ 2 }x + 2 \ln |x-1| + C\]
yup :)
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kk thanks.
Well, From the looks of it. it seems pretty good. good job. it seems like your good at this. ;)
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