Question

MEDALS!!Which expression is equivalent to tan(-x)cos^2x?
a.-sin xcos x
b.sin xcos x
c.tan x + sin^2x
d.tan x − sin^2x
e.-tan x − sin^2x

Answer 1

a.

Answer 2

\[\tan \left( -x \right)=-\tan x=-\frac{ \sin x }{ \cos x }\]

Answer 3

\[\tan (-x)=-\tan (x) \]\[-\frac{\sin (x) \cos (x) \cos (x)}{\cos (x)}=-\sin (x) \cos (x) \]