Question

question in comments

Answer 1

\[s_n=\frac{ a_1-a_1r^n }{ 1-r }\]when\[a_1=3\]r=0.795
h=5
So\[s_n=\frac{ 3-3*0.795^5 }{ 1-0.795 }\]\[s_n=\frac{ 3-3*0.31756720249}{ 0.205 }\]\[s_n=\frac{ 3-0.95270160747}{ 0.205 }\]\[s_n=\frac{ 2.04729839253}{ 0.205 }\]\[s_n=9.99\]

Answer 2

\[s_n=\frac{ a_1-a_1r^n }{ 1-r }\]when\[a_1=3\]r=0.637
h=5
So\[s_n=\frac{ 3-3*0.637^5 }{ 1-0.637 }\]\[s_n=\frac{ 3-3*0.10488108262}{ 0.363 }\]\[s_n=\frac{ 3-0.31464324786 }{ 0.363 }\]\[s_n=\frac{ 2.68535675214}{ 0.363 }\]\[s_n=7.4\]