Question

Calculus Help Please
Fan + Medal

Answer 1

@ganeshie8

Answer 2

\[\frac{ dy }{ \sqrt{1-y^2} }=2x dx\]

Answer 3

\[\sin^{-1}(y) =x^2+c\]

Answer 4

\[y=\sin(x^2+c)\]

Answer 5

Is that correct?

Answer 6

c_1+x^2 = integral_1^(y(x)) 1\/(r(1-xi^2)) dxi

Answer 7

@ParthKohli

Answer 8

Yes, that's right.

Answer 9

How do I do part B??

Answer 10

Can the sin(0+c)=3 for any value c?

Answer 11

Try graphing sin(x) for any value x.

Answer 12

There is no value for C.

Answer 13

So that initial point is not a point on the solution for y.