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\[\frac{ dy(1+y^2) }{ y } = \cos(x) dx\]
I know how to integrate cos(x)dx to be sin(x). But I cant figure out the first portion.
(sampling y(0))
(dy(x))\/(dx) = y(x) (cos(x)×1\/1)+y(x)^2
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y\'(x) = cos(x) y(x)+y(x)^2
first-order nonlinear ordinary differential equation
can u help me please @ONYXxELITE
yes hold on
I dont understand...
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dont understand what
Integrating the first part.
@ganeshie8 @ParthKohli Can you guys help?
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