Question

2-2cosx-sin^2x-1=0

Answer 1

@jim_thompson5910 can u help me with this one? i am try to simplify it

Answer 2

combine like terms
-2 cos x - sin² x + 1 = 0

Substitute (1 - cos² x) for sin² x
-2 cos x - (1 - cos² x) + 1 = 0

cos² x - 2 cos x = 0
now you can factor

Answer 3

-2 cos x - (1 - cos² x) + 1 = 0

Answer 4

after this step i am lost

Answer 5

did u take -2+1=-1 then -1-1=-2?

Answer 6

wait i see now

Answer 7

wait wouldn't there be a negative in front of cos^2x

Answer 8

no, the negative gets distributed

Answer 9

oh ok thanks!

Answer 10

you're welcome