Help pleaseeee!!!! https://i.imgur.com/eNEDmse.png
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (naate):
ohhh im sorry i would luv to help but i suck at algebra lol
OpenStudy (baby_bear69):
It's okay, know anybody who can help?
OpenStudy (naate):
yes!
OpenStudy (naate):
mind if i tag em?
OpenStudy (baby_bear69):
go ahead!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (naate):
ok, awesome! your very pretty by the way
OpenStudy (eboogie4):
Haha bro i was sayin the same thing
OpenStudy (baby_bear69):
Thank you!
OpenStudy (naate):
@SnuggieLad
OpenStudy (naate):
and no prob anytime !
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (baby_bear69):
@Zale101 @Conqueror @phi
OpenStudy (naate):
@Elsa213
OpenStudy (baby_bear69):
@Kainui
OpenStudy (naate):
lol sorry all my math people that i fanned are ofline right now :/
OpenStudy (baby_bear69):
ahh ._.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (naate):
well since i cant help ima leave lol but let me know if you need help in anything else! :) ttyl
OpenStudy (onyxxelite):
hello
OpenStudy (baby_bear69):
thank you! & hii can you help?
OpenStudy (twotreats):
yes
OpenStudy (baby_bear69):
Help please :3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (twotreats):
you need help n math
OpenStudy (baby_bear69):
yeah What is the value of h when the function is converted to vertex form?
g(x) = x^2 – 6x + 14
OpenStudy (twotreats):
Simplifying
g(x) = x2 + -6x + 14
Multiply g * x
gx = x2 + -6x + 14
Reorder the terms:
gx = 14 + -6x + x2
Solving
gx = 14 + -6x + x2
Solving for variable 'g'.
Move all terms containing g to the left, all other terms to the right.
Divide each side by 'x'.
g = 14x-1 + -6 + x
Simplifying
g = 14x-1 + -6 + x
Reorder the terms:
g = -6 + 14x-1 + x
OpenStudy (twotreats):
and that your answer
OpenStudy (twotreats):
you are welcome
Still Need Help?
Join the QuestionCove community and study together with friends!