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What is the minimum value for g(x) = x^2 – 10x + 16?
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-b/2a
thats going to be your vertex value
So minimum value is 2?
Well its a point in the form (x,y). Also how did you get 2?
I guessed XD
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ax^2+bx+c is the general form. x=-b/2a is the lowest point in terms of x. Then plug you x value back into g(x) = x^2 – 10x + 16.
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