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please help me figure this out, A container holds 15 pennies, 8 nickels, and 10 dimes. You will randomly select two coins without replacement. How many ways can you select the coins? How many ways can you select exactly 1 nickel? What is the probability that you select 2 pennies? What is the probability that you select a dime and then a penny?
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How many ways can you select the coins? 15*8*10= The answer
Okay, got that
How many ways can I select exactly one nickel?
That is not the number of ways to select the coins. you are selecting 2 coins, without replacement. You have 15 identical items, 8 identical items, and 10 identical items. This is a combination formula with identical items.
Makes sense
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