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Mathematics 19 Online
OpenStudy (98wday):

Can someone please walk me through the simplification of 2x^2-7x-15 ___________ (x+4)^2 Divided by x^2-10x+25 ___________ x+4

OpenStudy (peachpi):

start by factoring the numerators. Can you do that?

OpenStudy (98wday):

Yep give me a sec

OpenStudy (98wday):

Actually could I get some help on that I think I have the first one (2x+3)(x-2)(x-5) but I do not feel that is correct because when you distribute you get an x^3

OpenStudy (peachpi):

I'm not sure where the (x - 2) came from. I got (2x + 3)(x - 5)

OpenStudy (peachpi):

so the first one becomes\[\frac{ (2x+3)(x-5) }{ (x+4)(x+4) }\]

OpenStudy (98wday):

Yes have that

OpenStudy (peachpi):

try factoring the second one

OpenStudy (98wday):

would the first step be x^2 * 25?

OpenStudy (peachpi):

yes

OpenStudy (98wday):

So now we have 25x^2 and we have to split it into 2 terms that add up to -10 correct?

OpenStudy (peachpi):

right

OpenStudy (98wday):

So -10 and -15?

OpenStudy (peachpi):

-5 and -5

OpenStudy (98wday):

Dang your right idk why I was thinking 25 lol but yeah -5 and -5 obviously lol

OpenStudy (98wday):

We have x^2 -5x-5x+25

OpenStudy (98wday):

x(x-5) and 5(x-5)?

OpenStudy (peachpi):

It's (x -5)(x-5). What you have to do next is change the division sign to multiplication and flip the second fraction to its reciprocal.|dw:1461894956944:dw|

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