Question

Solve for d: 8g+6d=41
Solve for r: C=2(3.14)r

Answer 1

WILL MEDAL :-)

Answer 2

I can walk you through this.

Answer 3

Are the two questions separate of one another?

Answer 4

They are

Answer 5

Okay, I'll show you how to do the first one, then you can try the second one on your own.

Answer 6

Okay thank you

Answer 7

8g + 6d = 41
6d = 41 - 8g
d = (41-8g)/6
Is that what you are looking for?

Answer 8

if you think of
3=2+1

to solve for 2 you would subtract 1 from both sides
you do this because you want to use the opposite operation
so if you added 1 you would take away 1
if you multiplied you would divide
and vice versa

so to rearrange for 2 we do

3=2+1
3-1=2+1-1
since 1-1=0
2=2


so in your question
8g+6d=41

you want to solve for d

think of 8g as one value
so you want to subtract 8g from both sides to get

8g-8g+6d=41-8g
so we have
6d=41-8g

now we have 6d but we want d on its own
since we have 6 multiplied by d we must divide both sides by 6

to get

6d/6=(41-8g)/6
since 6/6 is one
we get

d=(41-8g)/6

now try to do the next one