There were 325 tickets sold for a basketball game. The activity cardholders tickets cost $1.50 and the non card holders ticket cost $2.25. The total amount of money collected was $525.00. How many of each kind of ticket were sold?

Question

giantrobot · Answer

Okay you have to use simultaneous equations. The first equation is simple. Let Cardholder's = x and non Cardholder's = y

Therefore 
$$x +y=325$$

The second formula can be derived from the costs.
$$1.5x + 2.25y=525$$

Now combine the formulas and solve for the x and y one at a time.


Here's how I would do it.

$$487.5-1.5y+2.25y=525$$
$$y=48$$
Logic dictates that
$$x=277$$