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Solve the system of equations algebraically. Show all of your steps Y= x^2+2x Y= 3x+20
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make y=y so result x^2 +2x = 3x +20 x^2 +2x-3x -20 = 0 x^2 -x -20 = 0 so you can factoriz it completly and will get (x-5)(x+4) = 0 x-5=0 x_1 = 5 x+4=0 x_2 = -4 hope you understand it sure
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