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Find the length of b. (Picture included)
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sin60 = b/2 do you know how many is sin60 = ?
sqrt3/2
Would it be sqrt3/2 over 2 as the final answer?
so do sin60 = b/2 1) evaluate what sin60 is with your calculator 2) isolate and solve for b
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I got sqrt 3/2 so do I do sqrt 3/2=b ?
so then you would bring over the 2 to the other side of the equal sign by multiplying it (inverse of division) \[\frac{ \sqrt{3} }{ 2 }(2) = b \]
Then do the 2's cancel? and I get left with square root of 3?
yes that can work
Is that the final answer? It says find to the nearest tenth
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