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Mathematics 20 Online
OpenStudy (august899):

Find the length of b. (Picture included)

OpenStudy (august899):

jhonyy9 (jhonyy9):

sin60 = b/2 do you know how many is sin60 = ?

OpenStudy (august899):

sqrt3/2

OpenStudy (august899):

Would it be sqrt3/2 over 2 as the final answer?

OpenStudy (calculusxy):

so do sin60 = b/2 1) evaluate what sin60 is with your calculator 2) isolate and solve for b

OpenStudy (august899):

I got sqrt 3/2 so do I do sqrt 3/2=b ?

OpenStudy (calculusxy):

so then you would bring over the 2 to the other side of the equal sign by multiplying it (inverse of division) \[\frac{ \sqrt{3} }{ 2 }(2) = b \]

OpenStudy (august899):

Then do the 2's cancel? and I get left with square root of 3?

OpenStudy (calculusxy):

yes that can work

OpenStudy (august899):

Is that the final answer? It says find to the nearest tenth

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