Question

Which is the quadratic variation equation for the relationship?

y varies directly with x^2 and y = 48 when x = 2.


A.
y = 12x^2

B.
y = 4x^2

C.
y = 4x

D.
y = x^2 + 25

Answer 1

y=kx
but for me y=kx^2
so plugging the numbers in 48=k(2)^2
48/4=12
..so my guess is A?
@MrNood can confirm?