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Mathematics 8 Online
OpenStudy (jekdidkdjrjrjjr):

fan + medal see pic

OpenStudy (jekdidkdjrjrjjr):

OpenStudy (jekdidkdjrjrjjr):

@marziman @welshfella

OpenStudy (jekdidkdjrjrjjr):

@TOMY12345

OpenStudy (jekdidkdjrjrjjr):

@jhonyy9

OpenStudy (lbarrientos1):

1=3rd tile

OpenStudy (tomy12345):

@Jekdidkdjrjrjjr Sorry, I don't really know.

OpenStudy (jekdidkdjrjrjjr):

actually i got it

OpenStudy (jekdidkdjrjrjjr):

i don’t need help i figured it out

OpenStudy (tomy12345):

@welshfella can you help me

OpenStudy (lbarrientos1):

\[\frac{ (x-2)(x+3) }{ x-2 }+\frac{ 10 }{ x-2 } ---> \frac{ x ^{2}-2x+3x-6+10 }{ x-2 }=\frac{ x ^{2}+x-4 }{ x-2 }\]

OpenStudy (lbarrientos1):

\[\frac{ (x-2)(x-1) }{ x-2 }+\frac{ 6 }{ x-2 } ---> \frac{ x ^{2}-3x+1 }{ x-2 }\]

OpenStudy (lbarrientos1):

\[\frac{ (x-2)(x-3) }{ x-2 }+\frac{10}{ x-2 } ---> \frac{ x ^{2}-5x+6 }{ x-2 }\]

OpenStudy (lbarrientos1):

check out if that works for you. i did it mentlly though so im sorry if the answer's wrong

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