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Algebra
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Which set of ordered pairs does NOT represent a function? A) (0, 1), (2, 2), (4, 8), (-2, 7), (5, 8) B) (0, 1), (2, 2), (4, 8), (2, 7), (5, 8), (7, 9) C) (-3, 6), (2, 7), (0, 5), (1, 5), (4, 9), (5, 4) D) (-4, 2), (-3, 2), (-2, 2), (-1, 2), (0, 2), (1, 2)
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@Elson
A function is where every x has only 1 y. a y can have multiple x and still be a function. Therefore, D is no a function because one x has multiple y values
Any more questions i can help with?
wait what is the answer for this question
yoou said is not D
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The question is asking for the one that is not a function, and D is not a function
ok i'm gonna tag u in my other question
K
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