Question

Someone help me with this Binomial please.

(-2z^2-14)-(-12z^2)

Answer 1

Simplifying
(-2z2 + -14) + -1(-12z2) = 0

Reorder the terms:
(-14 + -2z2) + -1(-12z2) = 0

Remove parenthesis around (-14 + -2z2)
-14 + -2z2 + -1(-12z2) = 0

Remove parenthesis around (-12z2)
-14 + -2z2 + -1 * -12z2 = 0

Multiply -1 * -12
-14 + -2z2 + 12z2 = 0

Combine like terms: -2z2 + 12z2 = 10z2
-14 + 10z2 = 0

Solving
-14 + 10z2 = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 10z2 = 0 + 14

Combine like terms: -14 + 14 = 0
0 + 10z2 = 0 + 14
10z2 = 0 + 14

Combine like terms: 0 + 14 = 14
10z2 = 14

Divide each side by '10'.
z2 = 1.4

Simplifying
z2 = 1.4

Take the square root of each side:
z = {-1.183215957, 1.183215957}