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I think it is 31 and 45 but i am not 100% sure
We have to find the lower quartile and the upper quartile...So we would first find the median of the list what would that be?
The list in order is... \(\LARGE{27,31,31,32,37,37,44,45,45,47,49}\)
@sbuck98 u there?
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Correct ^^ Now we would cross that number out and we would have two sets of list on either side of the crossed out number... |dw:1462477743992:dw|
@Awolflover1
@bmk614
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