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Write the integral in one variable to find the volume of the solid obtained by rotating the first‐quadrant region bounded by y = 0.5x^2 and y = x about the line x = 3.
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This is what i have so far. I know the radius is 3-x and i have to use the formula dV= 2pi*r*h*dx
Is that correct so far?
@Loser66
You have 2 parts, so that, you have to write 2 integrals, right?
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uhh i'm not sure?
|dw:1462492941739:dw|
For it, y = x is outer and y = 0.5x^2 is inner
|dw:1462493060019:dw|
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