Question

I will give medal if can help!

Find the number of real solutions for the equation.
x^2+8=0

Answer 1

The formula you use is b^2-4ac, but there's no c, so I don't know what to do

Answer 2

why not are there ,,c" ? what is there 8 than ?

Answer 3

@jhonyy9 b, c whatever! I'm just frustrated b/c I can't figure it out and I've been working on it for ages

Answer 4

ax^2 +bx +c = 0

this is the formula of quadratic - yes so than you can seeing now what is a and what b and what c - yes ?

Answer 5

wut

Answer 6

so there is b=0 bc bx dont exist - yes ?

Answer 7

Yeah I guess

Answer 8

or you can rewrite this equation same with

x^2 +0x +8 = 0 and solve it now in this way - ok. ?

Answer 9

So, 0 solutions?

Answer 10

why zero ?

Answer 11

0 real solutions, yes.

Answer 12

zero real solutions you think ? so than how need being the discriminant ?

Answer 13

I only needed to figure out how many solutions there are, so my question is answered. Thanks!

Answer 14

so than you like check it for zero real solutions the discriminant need being samler than zero

x^2 +0x +8 = 0

D = b^2 -4ac

D = 0^2 -4*1*8 = -32 so what mean that has zero real solutions

hope this is now understandably right easy sure

Answer 15

It was my pleasure!