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OpenStudy (csubero):
Can someone help me please?? https://gyazo.com/d941e83da9aaeaae3bfaf6ca7e74636e
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OpenStudy (csubero):
@Mehek14
OpenStudy (latinc):
think in fractions
OpenStudy (csubero):
so it would be 3/40 and 7/40?? math is not my best subject not gonna lie
OpenStudy (latinc):
close, but your base would be the total number of possibilities which in this case is the number of time he tossed the paper cup
OpenStudy (csubero):
so 50
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OpenStudy (csubero):
so it would be 3/50 and 7/50
OpenStudy (latinc):
yes
OpenStudy (latinc):
don't forget to reduce each fraction to lowest possible
OpenStudy (csubero):
ok so we would divide 3/50 and 7/50
OpenStudy (latinc):
divided the fraction to get the percent of the the probability but you should be find leaving them as fractions
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OpenStudy (csubero):
which would be 0.06 and 0.14
OpenStudy (latinc):
yes or 6% and 14%
OpenStudy (csubero):
oh ok thanks dude is that all??
OpenStudy (latinc):
if you but all three out comes in probability than yes that is all unless you have other quesitons?
OpenStudy (csubero):
yea I have 3 more do you mind helping me??
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OpenStudy (latinc):
post them as new questions
OpenStudy (csubero):
ok
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