Question

arccos(cos(-5pi/6)

Answer 1

how is 5pi/6 the answer

Answer 2

@ganeshie8 ?

Answer 3

cos (-5π/6) = -(√3)/2

f(x) = arccos x has a domain of [-1, 1] and a range of [0, π]. so
arccos (-√3)/2) is asking for the angle between 0 and π with a cosine of (-√3)/2)
That's 5π/6

Answer 4

ohh thanks!