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f(z)=2z-(3+i) I need to use this function to find the second iterate with an initial value of z_0=i
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@haleyelizabeth2017
\(f(f(z_0))\) is what you have to compute, right?
I think so...? I'm not entirely sure. I need to find the second iterate.
What did you find for \(f(z_0)\)?
2i-(3+i) ...?
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Yes, simplify it now (not necessary but makes life easier later)
i-3?
yes. Now compute \(f(i-3)\).
2(i-3)-(3+i) 2i-6-3-i i-9
yes. that's it.
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awesome, thank you (:
you're welcome
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