Question

MEDAL FOR BEST AND FASTEST ANSWER/RESPONSE!! :)

Answer 1

what

Answer 2

all you have to do is check this...

Answer 3

Group A most likely has a lower mean age of painting students. This is because the mean generally lies in the middle of the two extreme values. Because Group A's high extreme is lesser that Group B's high extreme, Group A has a lower mean average. To prove this, all you have to do is find the mean of both groups. So, you add up all of the numbers, then divide by how many numbers there are.

Group A:
9+10+10+10+10+10+10+10+15+15+15+15+15+15+15+15+17+17+17+17+17+17+17+17+19+19+19+19+19+19=154
154÷30=5.1333

Group B: 10+10+10+10+10+10+14+14+14+14+14+17+17+17+17+17+17+25+25+25+25+25+28+28+28+28+29+29+29+29=164
164÷30=5.4666

Answer 4

ok and

Answer 5

that is my answer to the question^^

Answer 6

so all I have to do is tellu if ur right or wrong

Answer 7

yes and if there is any improvements i need to make etc.

Answer 8

ok i guess i can do that

Answer 9

@WhatTehHeck @Elsa213 @rebeccaxhawaii @TheSmartOne @ilovemath14 @aaronq @ganeshie8 @likeabossssssss @Vocaloid @mathmale @niko

Answer 10

ok by you can just ask them i guess

Answer 11

Are you sure you added everything correctly?

Answer 12

\(\Huge\color{#EB00FF}{\text{WELCOME}}\)\(\Huge\color{blue}{\text{TO}}\) \(\Huge\color{green}{\text{OPEN}}\)\(\Huge\color{purple }{\text{ STUDY!!!!!!!!!!!}}\) \(\Huge\heartsuit\) no mass tagging plz

Answer 13

oops sorry!

Answer 14

i thought so...that is why i was asking you :)
@ilovemath14

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ilovenikosm
oops sorry!
\(\color{#0cbb34}{\text{End of Quote}}\)
np u rstill new at os so just meber next time :)

Answer 16

i will!

Answer 17

thx

Answer 18

no problem!:)

Answer 19

what? @ilovemath14

Answer 20

that does not make any sense @ilovemath14 ...