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Mathematics 8 Online
OpenStudy (logan13):

What is the value of x? Round to the nearest tenth.

OpenStudy (thefurball):

Is there more to the question?

OpenStudy (mysticfury):

do you know the Pythagorean theorem ? that is what you need to use to solve it

OpenStudy (logan13):

26

OpenStudy (mysticfury):

is that what you think the answer is? @logan13

OpenStudy (logan13):

yea

OpenStudy (mysticfury):

well lets walk through it 18^2 + b^2 = 28^2 18 x 18 =324 28 x 28 = 784 324 + b = 784 784 - 324 = 460 x = \[\sqrt{460}\]

OpenStudy (mysticfury):

\[\sqrt{460}\] = 21.4

OpenStudy (logan13):

so 21

OpenStudy (mysticfury):

"What is the value of x? Round to the nearest tenth." it wants you to round to the tenth :)|dw:1462826211336:dw|

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