Question

The equation 2x^2 - 2x - 12 = 0 is factored. Each factor is set equal to zero. What are these two equations?

A. 2x - 6 = 0, x + 2 = 0
B. 2x - 3 = 0, x + 4 = 0
C. 2x - 4 = 0, x + 3 = 0
D. 2x + 6 = 0, x - 2 = 0

Answer 1

A

Answer 2

Because (2x-6)(x+2)=2x^2-2x-12

Answer 3

Using the factor by grouping method you would do the following steps:
2x^2 - 2x - 12 = 0

2x^2 + 4x - 6x - 12
2x(x + 2) -6(x+2)
(2x-6)(x+2) = 0

So to find the roots, you would need to set each of them equal to zero.
2x - 6 = 0 ; x + 2 = 0