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Find the diameter of the circle (x - 4)2 + (y + 6)2 = 16. A) 2 B) 4 Eliminate C) 8 D) 16
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\[\huge\rm (x-h)^2+(y-k)^2=r^2\] circle equation where (h,k) is the center and r is radius
we know that \[\huge\rm d= r \cdot 2\] d=diameter
ok
so what's the radius ?
i dont know what to do to be honest
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\[ (x - 4)^2 + (y + 6)^2 = 16\] compare this equation with the general equation of a circle
what number is replaced by r^2 ?
i figure it out. is it b?
how did you get b?
read my 2nd comment diameter = radius times 2
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no c
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