Question

The sum of the square of 3 consecutive positive integers is 110. What are the numbers?

Answer 1

5,6,7 i used reasoning

Answer 2

but you can solve it algebraically too

Answer 3

5, 6, 7. 25 + 36 + 49 is 110. So what they said ^

Answer 4

If a equals 5 than yah it works well ^_^

Answer 5

(A^2)+([A+1]^2)+([A+2]^2)=110

Answer 6

@AloneS

Answer 7

@死は最高です

Answer 8

Lol thanks ;)