Question

see attachment for question

Answer 1

do i use the same formula b^2-4ac?

Answer 2

@Erak

Answer 3

That's only the part inside the square root, so you'd have to use the whole quadratic formula.

Answer 4

\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 5

so do you can solve it ?