Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.

What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.
P(red and yellow) ≈ %

Question

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.
 
What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.
 P(red and yellow) ≈        %

bmk614 · Answer

P(AthenB)= P(A)*P(B)
P(A)=Red/Total
Since the marble is not being replace, there is one less in the bag. So P(B)=Yellow/(Total-1)