HELP FOR A MEDAL PLEASE
A: 6x - 3y = -4 B: -4x - y = 5 To solve this system of equations by elimination, what could you multiply each equation by to cancel out the y-variable? A) Multiply A by 2 and B by 3 B) Multiply A by 1 and B by -3 C) Multiply A by 5 and B by -4 D) Multiply A by 3 and B by -2
I have no idea where to start
eliminating is to cancile out one part of the equation
B seems very Nice, why not test it out?
dont give out answer like that @latinC
lol hmmmm lets test B out XD
? what answer? Im just saying lets test B out
have you ever think that she want to learn
lol nawww who likes learning
thats why you test the answer for proof, math is all about proof. that is why the back of every math textbook has the answers
just go way guys
I would have to agree. Answer one question now is not as valuable as answer many later due to understanding what to do.
No! it is like when you get your math test back and you see all the right answers, you can either find out how to get the right answer or throw the test in the garbage
so lest eliminate the Y
It is okay if I know the answer but @12man yes you are correct I would like to know how you got that answer, so that if this question comes up again or something similar to it I know how to do it.
Using replacement and test works for multiple choice speed. Open answer requires understanding the method.
bye guys
Im a Y in this equation:(
A: 6x - 3y = -4 --> by 1 --> 6x - 3y = -4 B: -4x - y = 5 --> By -3 --> 12x +3y = 12 -------------- 18x + 0 = 8 y-variable eliminator; can solve for x. Which option multiplies every member of equation A by 1 AND multiplies every member of equation B by -3 ?
@kalijah13
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