The value of y varies directly with x², and y = 64 when x = 4.

What is the value of y when x = 6?

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Question

The value of y varies directly with x², and y = 64 when x = 4.
 
What is the value of y when x = 6?

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sissyedgar · Answer

@ShelbyWyatt

usukidoll · Answer

are you sure it's not cubed? 
I'm picturing this
y = x^2
and then to get y = 64 I have to have x = 8...maybe it's just me tired from exams

lncognlto · Answer

its y = k(x^2)

lncognlto · Answer

:P how are exams going? @UsukiDoll

sissyedgar · Answer

The x is cubed... x²
And which number is the K and which the x?

usukidoll · Answer

just finished my last one... I feel the same way as yesterday.

sissyedgar · Answer

Wait.. is it 8?

usukidoll · Answer

is it possible to show a screenshot of the problem so I can see if x^3 or x^2?

sissyedgar · Answer

It's x^2...
But here's the screenshot...

lncognlto · Answer

well congrats! mine start next week so I bid you adieu for now.

usukidoll · Answer

wow... it could be x^2 k = 64
if x = 4
4^2k=64
16k=64
k = 64/16 = 4

so maybe now we need to find y = 6^2 (k) ?

shelbywyatt · Answer

y=(x*x)*4

usukidoll · Answer

x = 6 was mentioned so y = 6 x 6 and from earlier that k was 4
so our real equation to solve is 
y = 6 x 6 x 4

sissyedgar · Answer

Soooo....
y=(6*4)*4?

shelbywyatt · Answer

6*6=36 36*4

sissyedgar · Answer

36 * 4 = 144

shelbywyatt · Answer

yeah thats my answer

sissyedgar · Answer

Okay.
Thankz guyz!!