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could anyone solve 1/16=64^4x-3 ? without looking it up
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much do 4x-3 first very simple x=7/12
must not much oops
i know the answer was just looking for the work
\[\dfrac1{16}=64^{4x-3}\]right?
\[\dfrac1{16}=64^{4x-3}\\~\\4^{-2}=(4^3)^{4x-3}\\~\\4^{-2}=4^{12x-9}\\~\\-2=12x-9\\~\\7 = 12x\\~\\\boxed{x=\dfrac{7}{12}}\]
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hey can you help me with another one ? @geerky42
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