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1. A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note?
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ok, u hv to use the formula \[v=f \lambda \]
f=frequency
v=velocity of sound
\[\lambda \]= wave length
f=?
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speed of sound nd wavelength given
pitch is high if the frequency is high
pitch will b low if frequency is low
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