Question

How large do we have to choose n so that the approximations Tn and Mn to the integral in part (a) are accurate to within 0.0001?

Answer 1

K = 154.942064, n = 10 \[0.0001 \le \frac{ 154.942064(2-1)^3 }{ 12(10^2) }\]\[0.0012n^2 \le 154.942064\]\[n^2 \le 129118.3867\]\[n \le \sqrt{129118.3867}\]\[n = 359.329932\]

Answer 2

The answer is wrong though, :(