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OpenStudy (iwanttogotostanford):
@freckles
OpenStudy (mjdennis):
Is that \[\sqrt{11-x}\] ?
OpenStudy (mjdennis):
Do you know what a domain is? That is a good start. If you don't, try searching "domain and range and it will help.
OpenStudy (iwanttogotostanford):
@mjdennis yes a domain is a set of real numbers, and the x-axis
OpenStudy (iwanttogotostanford):
please @mjdennis
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jhonyy9 (jhonyy9):
do you know what is the domain of squarroote - where is defined ?
OpenStudy (iwanttogotostanford):
@jhonyy9 no, i don't. I just need the whole process of how to solve this problem in steps please if you can.
jhonyy9 (jhonyy9):
so there are inside radical 11-x yes ?
for defined domain of radical you need to know that this is defned on 11-x >0 so what mean that
11-x >0
or do you can solve it now ?
jhonyy9 (jhonyy9):
please collaborate
OpenStudy (iwanttogotostanford):
ok, i got x<-0+11 @jhonyy9
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OpenStudy (iwanttogotostanford):
@jhonyy9
jhonyy9 (jhonyy9):
no
jhonyy9 (jhonyy9):
how you solve an inequalitie ?
OpenStudy (iwanttogotostanford):
I thought that was how...
OpenStudy (iwanttogotostanford):
how do i then>
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jhonyy9 (jhonyy9):
11-x>0 add to both sides x and will get
11 > x yes ?
jhonyy9 (jhonyy9):
ok. ?
OpenStudy (iwanttogotostanford):
and then what? I don't know what to do after that.... @jhonyy9
OpenStudy (iwanttogotostanford):
@jhonyy9
OpenStudy (iwanttogotostanford):
here are my answer choices btw: All real numbers except 11
x > 11
All real numbers
x ≤ 11
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OpenStudy (bunbunbun):
basically means that ur answer should be:
domain is 11>x
it may also be x<= 11
OpenStudy (bunbunbun):
so it is the last answer! c:
x ≤ 11
because x ≤ 11 is the same as 11>x
and square root 0 is 0 so domain can include 11