Question

Which points satisfy this linear quadratic system of equations?
x+y=1
y=4x-3-x^2

Answer 1

Set both equal to y, so you'd need to change the first one.

x+y = 1
y = 1-x

Now set both equations equal to each other and let it equal 0.

1-x = 4x-3-x^2
0 = -x^2 + 5x - 4

Put it in standard form, and now factor it.