Question

Solve for x: 2 over 5 plus 3 over 5 x equals quantity x plus 5 over 10.

Answer 1

\[\frac{ 2 }{ 5 }+\frac{ 3 }{ 5x }=\frac{ x+5 }{ 10 }\]
\[\frac{ 3 }{ 5x }=\frac{ x+5 }{ 10 }-\frac{ 3 }{ 5 }=\frac{ x+5-6 }{ 10 }=\frac{ x-1 }{ 10 }\]
cross multiply and solve for x,either by quadratic formula or by factoring.

Answer 2

correction write 2/5 instead of 3/5.

Answer 3

can you help me with the factoring?

Answer 4

\[\frac{ 3 }{ 5 x }=\frac{ x+5 }{ 10 }-\frac{ 2 }{ 5 }=\frac{ x+5-4 }{ 10 }=\frac{ x+1 }{ 10 }\]
\[5x \left( x+1 \right)=3 \times 10\]
\[5 x^2+5 x=30\]
\[5 x^2+5 x-30=0\]
divide by 5
what do you get?

Answer 5

-5

Answer 6

i mean -3

Answer 7

after dividing by 5
\[x^2+x-6=0\]

Answer 8

\[x^2+(3-2)x-6=0\]
\[x^2+3x-2x-6=0\]
now take common and make factors.

Answer 9

what do you mean by take common?